std::is_copy_assignable, std::is_trivially_copy_assignable, std::is_nothrow_copy_assignable
From cppreference.com
Defined in header <type_traits>
|
||
template< class T > struct is_copy_assignable; |
(1) | (since C++11) |
template< class T > struct is_trivially_copy_assignable; |
(2) | (since C++11) |
template< class T > struct is_nothrow_copy_assignable; |
(3) | (since C++11) |
1) If
T
is not a referenceable type (i.e., possibly cv-qualified void or a function type with a cv-qualifier-seq or a ref-qualifier), provides a member constant value
equal to false. Otherwise, provides a member constant value
equal to std::is_assignable<T&, const T&>::value.2) Same as 1), but uses std::is_trivially_assignable<T&, const T&>
2) Same as 1), but uses std::is_nothrow_assignable<T&, const T&>
T
shall be a complete type, (possibly cv-qualified) void, or an array of unknown bound. Otherwise, the behavior is undefined.
Helper variable templates
template< class T > inline constexpr bool is_copy_assignable_v = is_copy_assignable<T>::value; |
(since C++17) | |
template< class T > inline constexpr bool is_trivially_copy_assignable_v = is_trivially_copy_assignable<T>::value; |
(since C++17) | |
template< class T > inline constexpr bool is_nothrow_copy_assignable_v = is_nothrow_copy_assignable<T>::value; |
(since C++17) | |
Inherited from std::integral_constant
Member constants
value [static] |
true if T is copy-assignable, false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator() (C++14) |
returns value (public member function) |
Member types
Type | Definition |
value_type
|
bool
|
type
|
std::integral_constant<bool, value> |
Possible implementation
template< class T> struct is_copy_assignable : std::is_assignable< typename std::add_lvalue_reference<T>::type, typename std::add_lvalue_reference<const T>::type> {}; template< class T> struct is_trivially_copy_assignable : std::is_trivially_assignable< typename std::add_lvalue_reference<T>::type, typename std::add_lvalue_reference<const T>::type> {}; template< class T> struct is_nothrow_copy_assignable : std::is_nothrow_assignable< typename std::add_lvalue_reference<T>::type, typename std::add_lvalue_reference<const T>::type> {}; |
Notes
The trait std::is_copy_assignable
is less strict than CopyAssignable
because it does not check the type of the result of the assignment (which, for a CopyAssignable
type, must be an lvalue of type T
) and does not check the semantic requirement that the argument expression remains unchanged. It also does not check that T
satisfies MoveAssignable
, which is required of all CopyAssignable
types.
Example
Run this code
#include <iostream> #include <utility> #include <type_traits> struct Foo { int n; }; int main() { std::cout << std::boolalpha << "Foo is trivally copy-assignable? " << std::is_trivially_copy_assignable<Foo>::value << '\n' << "int[2] is copy-assignable? " << std::is_copy_assignable<int[2]>::value << '\n' << "int is nothrow copy-assignable? " << std::is_nothrow_copy_assignable<int>::value << '\n'; }
Output:
Foo is trivally copy-assignable? true int[2] is copy-assignable? false int is nothrow copy-assignable? true
See also
(C++11)(C++11)(C++11) |
checks if a type has a assignment operator for a specific argument (class template) |
(C++11)(C++11)(C++11) |
checks if a type has a move assignment operator (class template) |